(2x+3)(x-2)-(x-5)^2=21

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Solution for (2x+3)(x-2)-(x-5)^2=21 equation: 



(2x+3)(x-2)-(x-5)^2=21

We move all terms to the left:

(2x+3)(x-2)-(x-5)^2-(21)=0

We multiply parentheses ..

(+2x^2-4x+3x-6)-(x-5)^2-21=0

We get rid of parentheses

2x^2-4x+3x-(x-5)^2-6-21=0

We add all the numbers together, and all the variables

2x^2-1x-(x-5)^2-27=0

We move all terms containing x to the left, all other terms to the right

2x^2-1x-(x-5)^2=27

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